Connection Status:
Competition Arena > SwimmersDelight
SRM 266 · 2005-10-01 · by supernova · Search
Class Name: SwimmersDelight
Return Type: int
Method Name: longestJump
Arg Types: (vector<int>, vector<int>)
Problem Statement

Problem Statement

You want to cross a river 10 feet wide and there are 2 stones in the water you can jump on. A few jumps are needed, but your only concern is the longest one. This is obviously the most problematic, so you wish to choose a path that makes this jump as small as possible.

The length of a jump between two stones of coordinates (x1,y1) and (x2,y2) is defined as the Euclidian distance:
  sqrt((x1 - x2) * (x1 - x2)  +  (y1 - y2) * (y1 - y2))

You will be given a int[] x and a int[] y with exactly 2 elements each, representing the coordinates of the stones: (x[i],y[i]) is the location of the i-th stone. The edge of the shore on which you initially stand has an x-value of 0 and could take any y-value. Thus, the minimal distance between the shore and the first stone you jump on is the x-value in the location of that stone. The edge of the other shore has an x-value of 10 and could take any y-value as well.

Return the distance of the longest jump you need to make, rounded to the nearest integer.

Notes

  • You may jump on the 2 stones in any order, or just on one stone.

Constraints

  • x and y will each contain 2 elements.
  • All values in x are between 1 and 9, inclusive.
  • All values in y are between 0 and 10, inclusive.
  • The two stones are not in the same location.
  • No actual distance will be more than 1e-4 close to some integer + 0.5.
Examples
0)
{3,7}
{5,5}
Returns: 4

The three stones are arranged in a line, so the strategy is quite simple here: you first jump on the stone at (3,5), then on the stone at (7,5) and you finally reach the other shore at (10,5). The longest jump has a length of 4 feet: from (3,5) to (7,5). If you like to play around, you can follow the path (0,5) - (7,5) - (3,5) - (10,5), but this is not optimal since you have to make a jump of 7 feet! Thus, the correct answer is 4.

1)
{3,6}
{5,2}
Returns: 4

The path you should take is (0,5) - (3,5) - (6,2) - (10,2). Between (3,5) and (6,2) there is a distance of sqrt(3*3 + 3*3) = 4.2426. There are no jumps longer than this and because the answer is rounded to the nearest integer, you should return 4.

2)
{1,1}
{4,6}
Returns: 9

If you can jump 9 feet at once, chances are you are also a good swimmer ...

3)
{3,8}
{0,10}
Returns: 7

Only the stone at (3,0) is used in this case. The stone at (8,10) is more than 7 feet away from both the shore and the stone at (3,0).

4)
{4,2}
{5,5}
Returns: 6

The river can be a good initiation in the triple-jump technique. But you can also skip the stone at (2,5), as you need to take a 6 feet jump anyway.

Submissions are judged against all 125 archived test cases, of which 5 are shown here. Case numbers match the judge’s.

Coding Area

Language: C++17 · define a public class SwimmersDelight with a public method int longestJump(vector<int> x, vector<int> y) · 125 test cases · 2 s / 256 MB per case

Submitting as anonymous